12. The equilibrium constant, Kc, for the decomposition of COB COBrz(g) = CO(g) + Brz(g) is...

Question

Question

science chemistry

Answer 1

Answer #1

For 1st reaction:

Kc = [CO][Br2]/[COBr2]

= 0.190

For 2nd reaction:

Kc’ = [COBr2]^2 / [CO]^2[Br2]^2

= [COBr2] / [CO][Br2] ) ^2

= (1/Kc)^2

= (1/0.190)^2

= 5.26^2

= 27.7

Answer: E

Answer 2

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