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5. Assume a country whose GDP per capita was $1,000 in 1968 and $100,000 in 2018. What is approximately the average annual gr

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Answer #1

(5) (c)

If annual growth rate be r, then

1,000 x (1 + r)50 = 100,000

(1 + r)50 = 100

Taking 50th root,

1 + r = 1.0965

r = 0.0965 = 9.65% ~ 10%

(6) (c)

Taking natural logarithm,

ln z = 3 ln x = 3 x gx where gx = ln x

ln z = 3 x 0.1 = 0.3

(7) (d)

Income inequality is a disbenefit arising from growth.

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