Volume of the gas (V) = 1.5 L
Pressure (P) = 733 mmHg
Temperature (T) = 46 oC = (46 + 273) K = 319 K
Moles of the gas (n) = m/M
where,
m = mass of the gas = 4.47 g
M = molar mass of the gas
Universal gas constant (R) = 62.36 mmHg.L/mol.K
Now, substituting these values in the ideal gas equation to get,
PV = nRT
or, PV = mRT/M
or, 733 mmHg x 1.5 L = (4.47 g x 62.36 mmHg.L/mol.K x 319 K)/M
or, M = 80.9 g/mol
Hence, the molar mass of the gas = 80.9 g/mol
PLEASEE ANSWER ASAPPPP Calculate the molar mass of of an unknown gas that weighs 4.47 grams...
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