Homework Answers
Q9:
MnSO4.4H2O(s) 
MnSO4(s) + 4 H2O
Mass of water lost = 2.005g-1.780g = 0.225g
Number of moles of water lost = 0.225g/18.0153g/mol = 0.0124894mol
Number of moles of hydrated salt = moles of water ÷4 = 0.0124894/4 = 0.003122346mol
Mass of hydrated salt = 0.003122346mol× 223.0618g/mol
= 0.6965g (Answer)
Mass percentage of MnSO4.4H2O = (0.6965g/2.005g)×100% = 34.74 %. (Answer)
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