Question

A. What is the kinetic energy of a 1.2 g particle with a speed of 0.800c? Express your answer in joules.

B. What is the rest energy of a 1.2 g particle with a speed of 0.800c? Express your answer in joules.

C.What is the total energy of a 1.2 g particle with a speed of 0.800c? Express your answer in joules to two significant figures.

Answer 1

Rest mass of the particle = mo=1.2g => mo = 1.2x603 Kg [:: 19 = 16-3 kg] speed of the particle = v = 0.800 C where c is the speed of light = 3x108 mis - V = 0.8 X3 X108 = 2.4 x 108 mis Kinetic energy of the particle = k = mc2 / >> *= 1.2*** *** |-Peugeot 1) -> KE 1.2 X163 x13x1.8) 1X10812 3 X10 3 K = 1.2 X163 x Ji - (0.8)2 K = 10.2 x 10"? [vio - 2) = 10.8x1="[vce -- K= 10.8 x 10's [6-6 - 1] = 10.8 X10'3 [1-67-1] J 3) K = 10.8x1013x0.67 J = K = 7.236 X1013 J =) K = 7.2 xlo 13 J (2 significant figure) B) Rest mags energy = Eo = moc? = E. = 1.2 x1-3 x (3x108) 2 J. = E. = 1.2 X10-3 X9 X1016 >> E. = 10.8 x 10!3 J - Eo = 1.08 x 10!' J =) £. = lol Xlolly (a sig. fig.) c) Total energy of the particle =T=k+ Eo 5) T = 7.236 X1013 + 10.8 xło!? J - T = 18.036 X1013 J = 118036 X2014 J * T = 1-881014 J (2 significant figures)