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The square in the reaction equation is an equilibrium sign.
Consider the following reaction: 2NOBr(g) 2NO(g) + Br2(g) If 0.485 moles of NOBr(g), 0.623 moles of NO, and 0.470 moles of Br
The equilibrium constant, K. , for the following reaction is 7.00x10- at 673 K. NHI(s) NH3(g) + HI(g) If an equilibrium mixtu
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Kc = [NO]^2 [ Br2 ]/INOBr]^2 Concentrations=Number of moles/ volume in L M = mol/V [NOBr] =0.485 /14.9 =0.0326 [NO] = 0.623/1

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