Question

Write the quantum numbers for

The last electron in zinc

The last electron in oxygen, if the second to last electron has n=2, l=1, ml=-1/2

The electron in potassium that has the highest potential energy

Answer 1

​​​​​​The aufbau principe was used to solve the questions.

Solution 10 Electronic configuration of zu: 15²25² 22635²3p' 45²3do 10=4, 1=0 m, = 0; ms = + 1/ 1-1/2 (The last election in zinc is located in 45² orbital) ③ The second last dection has n=2, l=1, m, = -₂ This electrion is located in ap orbital, spin down E-C of Oxygen 15325267 M Immo In is 2s 2p But second to last election is in ap orbital spin down, The last election commesponds to the following quantum numbers. (n=2, 1=1, m, = 1, m,- t/2. The last election is in 2P2 oreleital. Espin up) 0 E.c. of potassium 1s ²25 2p 3 5² 3p 43' 45' has highert potential energy. Quantum numbers n=4, 1=0 m, = 0 mg = +/ conseeponding to 45'