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Gas Law Stoichiometry 8. Lithium hydroxide, LiOH, is used in spacecraft to recondition the air by absorbing the carbon dioxid
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Answer #1

1st calculate the mol of CO2 reacted.

Given:

P = 258.0 mm Hg

= (258.0/760) atm

= 0.3395 atm

V = 625.0 L

T = 27.0 oC

= (27.0+273) K

= 300 K

find number of moles using:

P * V = n*R*T

0.3395 atm * 625 L = n * 0.08206 atm.L/mol.K * 300 K

n = 8.619 mol

From reaction,

Mol of LiOH required = 2*mol of CO2 required

= 2*8.619 mol

= 17.238 mol

Use:

Mass of LiOH = mol of LiOH * molar mass of LiOH

= 17.238 mol * 23.95 g/mol

= 413 g

Answer: 413 g

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