Question

Artificial sweetener packages are supposed to contain exactly 1 gram of material. Naturally, it is impossible to have exactly that amount every time so companies allow for a margin of error either way. If a company's packets have weights of 1.000 g, 1.002 g, 0.995 g, 0.990 g, and 1.002 g, what is the average percent error obtained?

a. 0.22 %

b. 0.9978 %

c. 99.78 %

d. 22 %

Answer 1

Average percent = error, 100%/6.000 -1) +(1002-1) +0.99$ abb. of foo1)+( oto.002 -0.005 -o0loto. = % 10 x 01011 % = 0.22 % 0.002)1 Coption-a)