First determine the LCM of 6 and 10. It is equal to 30 years.
Now determine the PW of both the machines
PW(HX1) = - 20,000-20,000(P/F,6%,6) -20,000(P/F,6%,12)- 20,000(P/F,6%,18)- 20,000(P/F,6%,24)
PW (HX1) = -$ 55,985
Similarly for machine 2
PW(HX2) = -34,000 -30,000(P/F,6%,10) - 30,000(P/F,6%,20) + 4000(P/F,6%,30)
PW (HX2,) =- $ 59,409.54
Capitalized cost = PW/I
Machine HX1, Capitalized cost = -$55,985/0.06 = -$ 933,083
machine HX2, capitalized cost = -$59409.54/0.06 = - $ 990,159
Select machine HX1.
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Engineering Economics
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