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A disk with a diameter of 0.6 m speeds up from 20 rad/s to 40 rad/s in 5.0 seconds. (a) How many revolutions does it go throu

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Answer #1

D - By motion ist equation - Za wewice 4 redise ② By motion 3rd eq nation - oa wetu Iso ped N= = 23.87 Jele. o= wp²-wir so rc

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Answer #2
10.368789900986544
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Answer #3

SOLUTION :


a.


Angular speed increases from 20 rad/sec to 40 rad/sec in 5 secs.

So the average angular speed = (20 + 40)/2 = 30 rad/sec

Angular distance moved = 30 * 5 = 150 rad. 

So, number of revolutions done = 150/(2 * pi) = 23.87 (ANSWER).


b.


Disc travels 

= no. of frevolutions * 2 pi r 

= 150/(2 pi) * 2 pi * 0.3 

= 45 m (ANSWER).


c. 


Angiular acceleration 

= incrtease in angular speed / time

= (40 - 20) / 5

= 4 rad / sec^2 (ANSWER).


d.


Linear accleration 

= angular acceleration * r 

= 4 * 0.3 

= 1.2 m/s^2 (ANSWER).

answered by: Tulsiram Garg
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