Answer:
The reaction for the trimethylamine
TMA + H2O --> TMAH+ + OH-
| TMA + H2O (excess) --> | TMAH+ + | OH- | |
| Initial | 0.085 | 0 | 0 |
| Change | -a | +a | +a |
| Equilibrium | 0.085 - a | a | a |
Kb = [a][a]/[0.085 - a] = 6.46 x 10-5
a2 + 6.46 x 10-5 a - 5.491 x 10-6 = 0
or a ~~ 0.002321 = [OH-]
and pOH = -log(0.002321) = 2.63 option C
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