2,40 Particle 1 is subjected to an acceleration a=-ku, particle 2 is subjected to akt, and...

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Question

science physics

Answer 1

Answer #1

Particle 2

a = -kt

dv/dt = -kt

v = -kt^2/2 + Vo

V = -0.1t^2/2 + 10

Image result for v t graph for decreasing acceleration

particle 1

a = -kv

dv/dt = -kv

dv/v = -kt

logv = -kt + logVo

log(V/Vo) = -kt

V = Voe^(-kt)

= 10e^(-0.1t)

2.5 2.0 1.5 1.0 0.5 0 2 3

Answer 2

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