Ans:
a)
Use Poisson distribution:
On average,there will be 3*0.54=1.62 storms in 3 years
So,
P(x>2)=1-P(x<=2)
=1-P(x=0)-P(x=1)-P(x=2)
=1-e-1.62*(1.620/0!+1.621/1!+1.622/2!)
=1-e-1.62*(1+1.62+1.3122)
=0.222
b)t=4/2=2
P(there is no storm within 2 years i.e. storms comes after 2 years)=P(T>2 yrs)=e-0.54*2=0.340
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