A reaction has ΔHºrxn = –201 kJ/mol and ΔSºrxn=-394 J/mol·K. Below what temperature is the reaction spontaneous?

A reaction has ΔHºrxn = –201 kJ/mol and ΔSºrxn=-394 J/mol·K. Below what temperature is the reaction...
A reaction has ΔHºrxn = –201 kJ/mol and ΔSºrxn=-282 J/mol·K. Below what temperature is the reaction spontaneous? Spontaneous below _________ °C.
Calculate ΔGºrxn for a chemical reaction with ΔHºrxn = 778 kJ/mol and ΔSºrxn = 145 J/mol·K at 298K. ΔGºrxn =__________kJ/mol
Consider the following reaction, for which ∆H° = -113.1 kJ/mol and ∆S° = -145.34 J/mol·K. 2NO(g) + O2(g) ⇌ 2NO2(g) Assume ∆H° and ∆S° do not vary appreciably with change in temperature. This reaction will only be spontaneous at a temperature _____(i)_____ than ______(ii)_____. (i) lower (ii) 298.15 K (i) higher (ii) 1285 K (i) higher (ii) 1285 K (i) lower (ii) 778 K (i) higher (ii) 778 K
For a particular reaction at 209.8 °C, ΔG = -318.09 kJ/mol, and ΔS = 994.40 J/(mol·K). Calculate ΔG for this reaction at -58.2 °C.
For a particular reaction at 134.8 °C, ΔG = -1319.75 kJ/mol, and ΔS = 863.35 J/(mol·K). Calculate ΔG for this reaction at -79.1 °C.
For a particular reaction at 139.3 °C, ΔG = 354.61 kJ/mol, and ΔS = 658.46 J/(mol·K). Calculate ΔG for this reaction at -55.9 °C.
For a particular reaction at 248.5 °C, ΔG = -874.51 kJ/mol, and ΔS = 646.50 J/(mol·K). Calculate ΔG for this reaction at -76.9 °C.
1. A reaction has AH = 100 kJ/mol and AS = 250 J/mol K. a. Is the reaction spontaneous at room temperature? b. If not, under what temperature conditions will it become spontaneous? 2. Consider the following reaction at 298 K: N204(g) = 2NO2(g) KP=0.142 What is the standard free energy change at this temperature? Is the reaction spontaneous at this temperature?
1.) Calculate ΔHºrxn ΔSsurr and ΔSºrxn to determine if the reaction is spontaneous at 298 K ΔHºf : PCl3(g) = -287 kj/mol ΔSºf : PCl3(g) = -3112 J/mol *K ΔSºf : P4(s) = 41.1 J/mol*K ΔSºf : Cl2(g)= 2230 J/mol *K P4(s) +6Cl2(g) ------> 4PCl3(g) 2.) Calculate ΔGºrxn from enthalpy and entropy values at 298 K 4NH3 (g) +5O2(g) -----> 4 NO(g) +6H2O(g) ΔHºf : NO(g) = 90.29 kj/mol ΔHºf: H2O(g) = -241.826 kJ/mol ΔHºf: NH3(g) = -45.9 kJ/mol ΔSºf : NO(g)...
a reaction has delta H = 100.0 kJ/mol and delta S = 250.0 J/mol K. Is the reaction spontaneous at room temperature? If no, at what temperature (in K and C) does this reaction become spontaneous?