Question

3 ! Required information In an emergency, it is sometimes the practice of medical professionals to immerse a patient who suffers from heat stroke in an ice bath, a mixture of ice and water in equilibrium at 0°C, in order to reduce her Part 1 of 3 body temperature. The average specific heat of human tissue at 20.0°C is 3.50 x 10 heat of fusion for water is 333.7 x 103 J/kg. J/kg.K. The latent points еВook If a(n) 84.6-kg patient whose body temperature is 42.5°C must have her temperature reduced to the normal range (37.0°C), how much heat must be removed? Hint Print MJ References 10

Answer 1

3. Q = MCAT = (84.6 kg) ( 3.50 x 107 fliegie) (425-37) Q = 1.63x100 I = 1063 MJ 3.7 X 4. Quelt = ML = ( 760 g) ( 333.7x10 35/13) = 2.54 xlo6 g = 2.54 MJ 2.54) S. Mice-melted = (162) (760) = 4.88 kg ice remaining = 760-4.88 = 2.72 kg