Question

12 only C, H, anorganic acid Completely When 0.472 g of an organic acid Containing only C, H, and o was burned Completely in the presence et Op it gives 0842 g CO2 and 0.3449 42o. Given that the molar mass is known to be approximately 1222.24 almol. Find the emperical and molecular formula. a Chemical Equation 6 What is given? c. behat is needed?

Answer 1

Chemical equation Caty O₂ + mo liven: combustion CO2 + H₂O 0-472g 0-8429 0.3449 of H₂O Getty Oz of co2 Motay mass - 222.24 mol * Conversion of mass to rooles CO 0-8439 of CO2 X imol of CO2 44g of co2 = 0.0191 mol of CO2 H₂O 0-3449 of H20 x 1 mol of H2O 189 of H2O 20.0191 mol of H₂O NO of motes of cin CO = 0.0191 mot of c. No. of moles of H in H2O = 24.0-0191 mol ofH = 0.0382 mol of H. * Conversion of motes to mass 0.0191 motes of c x129 of C I mot of c = 0.22929 ofc = 0.03829 of HI 0.0382 motes of H x 19 of H Imol of H c Total mass of organic compound = 0-4729 mass of oxygen total mass - mass of mass of hydrogen = 0.4729 - 0.22929 - 0.03829 mass of oxygen = 0.20469

Conversion of mass to moles 0,2046 9 of Oxygen x 1 mot of oxygen = 0.0128 mol. 16g of oxygen Moles Ratio Elements Mass (92 Carbon (C) 0.2292 0.0191 Hydrogen 0.0382 0.0382 0.0491 - 1-49 € 1 0-0128 0-0382 = 2.982 3 0.0128 0.0128 = 1 0-0128 Oxygen (0) 0.2046 0,0128 Empirical formulat C, H₂O, Empirical formula mass = 129+ 3g + 169 = 319 Motar mass = 222.949 mol- Molecular formulas (Empirical formula)n. n = Motar mass Empirical formula mass na 222.24 9 27.1697 319 Molecular formula 3 (C, 430,77 Molecular formula . C7H2107.