Question

Gaseous hydrocarbon A 0.271-9 sample of a gaseous hydrocarbon (CxHy) occupies 117 mL at 22.0°C at 735 torr. Calculate the molar mass of this hydrocarbon in g/mol. Express your answer as a number (not scientific notation) without units, for full credit, the last digit of your answer should be within 11 of the correct value, with an appropriate number of significant figures. Molar mass: g/mol. Complete combustion of 1.532 g of this gaseous hydrocarbon (CxHy) yields 4.640 g of carbon dioxide and 2.375 g of water. Calculate the moles of C and H in this amount of the hydrocarbon. Express your answers as a number (not scientific notation) without units, for full credit, the last digit of your answer should be within +2 of the correct value, with an appropriate number of significant figures. moles C in CyHy moles H in CyHy Determine the empirical and molecular formulas of this hydrocarbon. If a subscript in the formula is "1", enter it explicitly. Empirical formula: C Molecular formula: C

Answer 1

- 1000 Ideal bras Eqr il PV = nRT Where P- Presswe= 735 fori = 735x0.00131579 atm = 0.9671 atm - Volume = 117 ml = 117 L = 0.117 Asma R = bas constant = 0.082057 Latmk-mol- E lembertecture 29.0°C 22.0+ 273.15 = 295.15K = No of moles on = 0.9671 atmx 0.1172 0.004672 mol 0.082057 Latm Ki mol-'x 295:15K in Cxty Molar Mass = Mass = 0.211 g = 58.0 g/mol . No of moles 0.004672 mol = No of holes of COg = Mass = 4.640g = 0.1054 mal Molar Mass 44.01glmal As 1 mole CO2 contains I molec I No of modes of 6= 0.1054 moles = No of moles of C No of moles of H₂O = 2.3159 = 0.13183moles - 18.015 g/mol I As f mole to contains 2 mole H - No of moles of H= 0-13183x2= 0.26366 Ž 0.2637 moles . No of moles of Hin Ge Hy = 0.2637 mol o Mole ratio of CiH in G ty = 0.1054: 0.2637 Dividing by 0.1054 and converting to whole no, (8H = 1:2.5 Multiplying by 2 to convert this ratio to whale no. ration (: H= 285 & Empirical formula= Cg H5

Molar Mass of Getty Melar Mass of Cats No of Cette units in Molecular formula = = 58.0 glmal - 2 29.0g/mol o Modecular formular (Ca Hg)₂ = (y tho