Maintenance money for a new building has been sought. Mr. Price would like to make a donation to cover all future expected maintenance costs for the new building. These maintenance costs are expected to be 50,000 for the first increasing by 2000 per year for the first 10 years, 70000 for the 11th year increasing by 3% per year for the following 20 years and 130000 each year after that. There is also an additional overhauling cost of 200000 for the building every 20 years. The donation will be placed in an account that will pay 12% interest.
A- Detetermine the amount of this donation
B. What is the equivalent annual maintenance cost over the infinite service life of the building
A- To detetermine the amount of this donation | ||||||||||
We need to calculate in parts & add up the anwers of all parts as follows : | ||||||||||
Part--1 | ||||||||||
PV at Year 0 ,of maintenance costs for the 1st 10 years= | ||||||||||
Year | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
Annual maint.costs | 50000 | 52000 | 54000 | 56000 | 58000 | 60000 | 62000 | 64000 | 66000 | 68000 |
PV F at 12% | 0.89286 | 0.79719 | 0.71178 | 0.63552 | 0.56743 | 0.50663 | 0.45235 | 0.40388 | 0.36061 | 0.32197 |
PV at 12% | 44642.86 | 41454.08 | 38436.13 | 35589.01 | 32910.76 | 30397.87 | 28045.65 | 25848.53 | 23800.26 | 21894.18 |
NPV | 323019.33 |
Part--2 |
70000 for the 11th year increasing by 3% per year for the following 20 years |
ie. |
PV at Yr. 0 |
of the PV at end yr. 10 of the growing annuity starting with $ 70000 in year 11 |
growing at g=3% for years 12 to 20 |
ie. n=10 |
at an interest rate of 12% p.a. |
using PV of Growing annuity formula, |
PV(GA)=(P/(r-g))*(1-((1+g)/(1+r))^n) |
ie.70000/(12%-3%)*(1-(1.03/1.12)^10)= |
441229.36 |
PV at yr. 0 of the PV(GA) at end Yr. 10 = |
441229.36/1.12^10= |
142064.05 |
Part--3 |
130000 each year after that |
ie. From yr. 21 onwards |
so, we need to find |
the PV at Yr.0 |
of the PV at Yr. 20 end |
of the perpetuity of $ 130000 per year |
at r=12% |
PV at Yr 20 end of the perpetuity = |
130000/12%= |
1083333.33 |
PV at Yr.0 of the above PV of perpetuity= |
1083333.33/1.12^20= |
112305.66 |
Part--4 |
additional overhauling cost of 200000 for the building every 20 years |
PV at Yr. 0 of the perpetuity |
of the PV of a single sum at end Yr. 20 |
PV of the single sum of $ 200000 at end of 20 years= |
200000/1.12^20= |
20733.35 |
PV at Yr. 0 of the above sum perpetually = |
20733.35/12%= |
172777.92 |
Answer for A = | |
Sum of all the PVs at yr 0 | |
Part--1 | 323019.33 |
Part--2 | 142064.05 |
Part--3 | 112305.66 |
Part--4 | 172777.92 |
Amt. of this donation | 750166.95 |
B. Equivalent annual maintenance cost over the infinite service life of the building |
750166.95/20 yrs.= |
37508.35 |
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