Question

hi can you please help me understant how to know when to reject or fail reject ho

Aps/J0.250. 72) //30 9a05 1.oIS Perform the indicated hypothesis test using p-xalue method. 7) A medical school claims that/more than 28% of its students plan to go into general practice. It is found that among a random sample of1500f the school's students, 32 % of them plan to go into 7) HANDOU general practice. Find the P-value for a test of the schools claim. A) 0.3078 eIA.m P>0.2,-2CASe 30r ) Ho: P-0.2S )Hi: P>022Dght B) 0.1635 0.1539 )1s:d.32-0.2 D) 03461 i535 1.02 O-28 p.72)- ois 8) In a sample of88 childrer selected randomly froth one fown, it is found thafof them suffer from asthma. Find the P-value for a test of the claim that the proportion of all children in the town who suffer from asthma is equal to 11% B) 0.2843 ,a/n09aA) -0.2843 )clAmiPao. a) Ho: p-o.11 902157 D05686 2/8-0.11 ) p.31)&1-4. - 0.57 ) 333 51 Pa2x0-2 93: 0.5686 9) Find the P-value for a test of the claim thatmore than 50%of the people following a particular diet will experience increased energy. Of100randomly selected subjects who followed the diet 47 noticed an increase in their energy level. A) 0.5486 cIAm Pyo.s a) Ho: s0.s s)Hi: 9 0.5-hg b 10) An airline claims that the no-show rate for passengers booked on its flights isless than 6%Of380/ randomly selected reservations 18 were no-shows. Find the P-value for a test of the airline's claim. 02743 15:/i-a.5 902257 D) 0.7257 5) -.03 (0.5) (a.9) 05 100 10) B) b1230 ) 1/3100-096 1-09 ),1 A) 0.0746 90.3508 D0.1492 )cIAimipLo.0 a) Ho: p 0.0l 3) Hi pL00b-> left 11) A nationwide study of American homeowners revealed that 65% have one or more lawn mowers A lawn equipment manufacturer, located in Omaha, feels the estimate is too low for households in Omaha. Find the P-value for a test of the claim that the proportion with lawn mowers in Omaha is higher than 65 %. Among 497 andomly selected homes in Omaha, 340 had one or more lawn O12/8 0.06 -1.0 11) mowers. A) 00505 B) 0.0252 1 )370/917--65 ). 62 ১) 3321 023 G0.0559 D) 0.1118 3) .s bighy 12) A manufacturér claims that fewer than 6 % of its fax machines are defective. In a random sample of (97 kuch fax machines, 5 % are defective. Find the P-value for a test of the manufasturer's claim. HanDour A) 0.3264 ClAmi.06sa )as06 1) Ho: :.06 ) Hi: eL-0-let 13) In a sample of 47ndults selected randomly from one town, it is found that 9/of them have been exposed to a particular strain of the flu. Find the P-value for a test of the claim that the proportion of alladults in the town that have been exposed to thisatrain ofthe flu 8 % a 12) B) 0.1591 90.17363904 (D03409 -3t0920.09 Fail react Ho-C5t7 No SutFiEitnt ev.Dent 1o Suppor the clam L O. S) 1ו 253 O6.92 .0.1 13) C A) 0.0024 B) 0.0524 Go.0048 O.008L0.05 D) 0.0262 )dAm p,osxte 1/ Preject Ho- cAse ) sutficient eviDent to reget The claim ol 0.0 .6015 3) HiR 4) 9/47-.03 2.82 0024 x2=.009 .0s (.4) 41 0315

Answer 1

Solution:

From the given question, it is apparent that you are using the p-value to make a decision about the null hypothesis.

The decision rule based on the p-value is:

If the p-value is less than the significance level, then we reject the null hypothesis

If the p-value is more than the significance level, then we fail to reject the null hypothesis.

Suppose for question # 7, if the significance level is 0.05. The p-value that you have found is 0.1539.

The decision will be here:

Since the p-value is greater than the significance level 0.05, we, therefore, fail to reject the null hypothesis.

Similarly for question # 13. if the significance level is 0.05. The p-value that you have found is 0.0048.

The decision will be here:

Since the p-value is less than the significance level 0.05, we, therefore, reject the null hypothesis.

Hope it helps!