Question

After creating her standard curve for absorption versus the concentration (M) of FD&C Red 40, a student found that her best fit linear line for FD&C Red 40 2,243x + -0.006 was y Her Kool-Aid sample had an absorbance of 0.422. If 0.496 grams of Kool-Aid powder was used to prepare an 8-fl oz cup of her assigned flavor, what is the percent by mass of FD&C Red 40 in her 8-fl oz cup? Do not include the percentage sign in your answer. Pay attention to units. You are trying to find the mass percentage of red dye, so you need to know each variable in the equation in the manual. Note: These numbers are randomly generated, and will not be the same as your data in lab.

Answer 1

Given Y = 2,243 x + 6-0006) Hex kool-Aid Sample had an absorbance of 0.422. 0:496 grams of kool-Aid powder was used to prepare on B-floz cup her assigned flavos, The concentration of Red by means of the equation of the clear line is Y = 2,243 x + 6-0.006) => 2,24 3 X = Y-0.006 x = y-0.006 2,243 x = 0.422 -0.006 2,243 0.476 2,243 X = 1.85 x 10-4 The grams of red 40 present

496-429 = 11.85 x 10 q = mu mm = (185*104 polle) (8 98) (53814 ) / 1946 ung) = (1.65810-4) 10) (2.195x105] (495497) Indel / = 2:1 X10-59 0.0219 ..The game of red wo prezent -00213 The percentage of red 40; % Red 40 = gx100 g sample (0.021) (100) - 0.496 g 2.1 0.4969 = 4.23% Fthe percentage d ved 405 4.23%