Question

Use the References to access important values if needed for this question. What volume of propane (C3H8) is required to produce 113 liters of water according to the following reaction? (All gases are at the same temperature and pressure.) propane (C3Hg) (g) + oxygen(g)—>carbon dioxide (g) + water(g) liters propane (C3H2) Submit Answer Retry Entire Group 9 more group attempts remaining

Answer 1

1)
Balanced chemical equation is:
C3H8(g) + 5 O2(g) -> 3 CO2(g) + 4 H2O(g)

From above equation,
Volume of C3H8 required = (1/4)*volume of H2O
= (1/4)*113 L
= 28.25 L
Answer: 28.25 L

2)
Balanced chemical equation is:
C3H8(g) + 5 O2(g) -> 3 CO2(g) + 4 H2O(g)

From above equation,
Volume of CO2 produced = 3*volume of C2H8
= 3*180 L
= 540 L

Answer: 540 L