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How are there 8 stereoisomers for this molecule? I though it was determined by 2 raised...


image.pngHow are there 8 stereoisomers for this molecule? I though it was determined by 2 raised to the number of chiral centers (2^n). However when looking at this molecule I thought that there's only two chiral centers.
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Answer #1

There are 3 chiral centers (asymmetric carbons) in the given molecule, which are shown by asterisks.

So, there will be 23 = 8 stereoisomers possible for the given molecule, as shown below.

(i) (R, R, R)

(ii) (R, R, S)

(iii) (R, S, R)

(iv) (S, R, R)

(v) (R, S, S)

(vi) (S, R, S)

(vii) (S, S, R)

(viii) (S, S, S)

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