Question

Balance the following equation in acidic solution using the lowest possible integers and give the coefficient of water.

NO₃^-(aq) + I(aq)^- → NO(g) + I₂(s)

Answer 1

Unbalanced redox reaction is, NO, (aq) +I (aq) + NO (aq) + 1 (5) Step1: First write half reactions: Oxidation: 21 →I Reduction: NO, NO Step 2: Balancing oxidation half reaction 21 → +2e Step:3 Balancing reduction half reaction Balancing O: NO, NO+2H,0 Balancing H: NO, +4H* + NO + 2H,O Balancing charge: NO; +4H* +32 NO + 2H2O Step: 4 Equalizing theno of electron lost in oxidation half reaction and no of electrons gained in reduction half reaction. (21°12)x3 (NO, +4H* +3e → NO+2H,0)x2 Step 5:Adding both the half reactions : 61 +31+ 6e 2NO, +8H* +66 +2NO+ 4H20 21 +2NO3 +8H* +2NO+ 4H,0+31 Therefore, the balanced equation is shown below: 61 +2NO, +8H+ + 2NO+ 4H 0+31