2Fe3+(aq)+H2(g)→2Fe2+(aq)+2H+(aq). What is the emf for this cell when [Fe3+]= 3.90 M , PH2= 0.94 atm...
2Fe3+(aq)+H2(g)→2Fe2+(aq)+2H+(aq).
What is the emf for this cell when [Fe3+]= 3.90 M , PH2= 0.94 atm , [Fe2+]= 1.5×10−3 M , and the pH in both compartments is 3.80?
Homework Answers
![O.os a. pH = 3.8 = -log[ut] [+] = 1.5849x10 M Putting values is equation, 0.77-0.059 log £5 x103) (1.5849x1=) (3.9) 2 (0.94)](http://img.homeworklib.com/questions/6f1fe860-73f3-11ea-b44d-fb0c04b5b6c9.png?x-oss-process=image/resize,w_560)
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2Fe3+(aq)+H2(g)→2Fe2+(aq)+2H+(aq).
What is the emf for this cell when [Fe3+]= 3.90 M , PH2= 0.94
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