Question

carpet fibers have to be able to handle all kinds of foot traffic. the following shear modulus data

4. (18 points) Carpet fibers have to be able to handle all kinds of foot traffic. The following shear modulus data were collected for samples of a polymer carpet 0. different temperatures in a stress relaxation experiment where a constant suam (comparable to stepping on the carpet) was applied: 0.05 25°C 35°C log t (sec) Shear Modulus dyne/cm2 log t (sec) Shear Modulus dyne/cm2 2.8 1.2 1.5 3.25 x 100 3.17 x 100 3.08 x 10" 2.98 x 100 3.22 x 1007 3.08 x 10107 3.0 1.75 3.8 2.15 2.65 3.15 3.00 x 100 2.92 x 10" 2.83 x 100 2.79 x 10" 2.75 x 100 3.40 Determine the best value that you can for the shear modulus at 35°C (hot day) for the fiber after 10 seconds at 5% strain. Do not work this problem using the WLF equation. I want you to solve this using what you know about constructing master curves. Since there will be some inherent error in your answer, it is critical the explain and show your work. Hint: This problem can really be very simple wi simple calculations.

Answer 1

Cool day:

The plot of Shear modulus versus Log t can be drawn as follows.

3.25E+010 3.20E+010 Share Modulus (dyne/cm) 10 .01 3.05E+010 3.00E+010 2.950.0101 3 0 376 32 3. 4 Log t

Equation of the line: Shear modulus = -2.64317*10⁹ * Log t + 3.97242*10¹⁰

Hot day:

The plot of Shear modulus versus Log t can be drawn as follows.

3.30E4019 3.20E+010 3.10E+0101 30.00E010 2.90E+010 2.00E+010 2.70E+010. 15 Shear modulus (dyne/cm)

Equation of the line: Shear modulus = -1.95528*10⁹* Log t + 3.38276*10¹⁰