Question

Towns between 1 and 5 months old have a body weight that is approximately normally distributed with mean27.0 ograms and standard deviation - 3.5 grams to be the o w n ers The Sanderd al tuto intervals to intervals. (Round your answers to two decimal places) Convert the following (a) x 30 (c) 32<x<35 intervals (Round your answers to one decimal place.) Convert the following intervals to (d) -2.17 z (e) < 1.28 (1) -1.99 144 (a) If a row weighs 14 kilograms, would you say it is an unusually small animal explaining values and the figure above Yes. This weight is 3.61 standard deviation below the mean: 14 kg is an unusually low weight for a town Yes. This weight is 1.81 standard deviations below the mean; 14 is an unusually low weight for a town No. This weight is 3.61 standard deviations below the mean; 14 kg is normal weight for a few No. This weight is 3.61 standard deviations above the mean: 14 kg is an unusually high weight for a few No. This weight is 1.81 standard deviations above the mean: 14 kg is an unely high weight for a few (h) If a rown is unusually large, would you say that the value for the weight of the town will be close to 0, -2, or ? Explain it would have a large positive z, such as 3. It would have a negative, such as - 2 It would have a rof 0.

Answer 1

Fawnsbetween 1 and 5 months old in Mesa Verde National Park have a bodyweight that is apx normally distrubuted with mean μ=27.0 kilogram and standard deviation σ=3.5 kilograms (based oninformation from The Male Deer of Mesa Verde National Park by G.W.Mierau and J.I. Schmidt, Mesa Verde Museum Assoc). Let x be theweight of a fawm in kilograms. Comvert each of the following xintervels to z intervals.

a. x<30
---->   z < ((30) -(27.0))/(3.5)
---->   z < 0.86

b. 19< x
---->   z > ((19) -(27.0))/(3.5)
---->   z > -2.29
---->   OR: -2.29< z

c. 32<x<35
---->   ((32) - (27.0))/(3.5)< z < ((35) -(27.0))/(3.5)
---->   1.43 < z < 2.29

converting following z to x interval is

d) -2.17<z

x=27-2.17*(3.5)=19.4

19.4<x

e)

z<1.28

x=27+1.28*(3.5)=31.5

x<31.5

f)

-1.99<z<1.44

x=27-1.99*(3.5)=20.0

x=27+1.44*(3.5)=32.0

20.0<x<32.0