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*Question 241: Two Slit Interference A Young's two slit experiment is set up with two slits separated by a distance 0.1 mm. A screen is placed 20 cm from the slits. If light of wavelength 500 nm is shone through the slits how far apart (on the screen) are the successive maxima? Select one: O a. 0.5 mm O b. 1 mm O c. 1 cm d. 1 nm O e. 31 cm

Answer 1

18-24 We know from Young's two olit experiment, the distance beth two maxima in x = 1 I here D = Distance beth sliz and pereen. here, D = 20em da distance bet "Amo slits. 220x10?m ja navelength of light - x = distance beth two maxima. = 500810-9 m. de 0.1 mm - 0.1*10*3m 4. X(20x10-2)x(500 x1099) d = 500 nm. (0.1*10-3) :14103 m - 1mm 2. The anecessive maxima are 1 mm. apart (on the more 8.244 The sit width (a)= 5em=58102m; the 1st minima (n=1) is observed out an angle Let it be the wavelength of mierowave, (On) = 37° now, we know, for single slit experiment Sinon = n l here on=370 u noi on = a fi non a = (5x 102m. on (57102) x sin(37°) 3001 x 102m 3.01 em. The wone length of microwave in @ 3.01 cm)