Question

Calculate the percent by mass of a 3.00 m solution of benzoic acid, HC6H3CO2, in benzene, C6H6.

Answer 1

- Answer molality = moles of Solute Tilky ot Solvent 3.00m = moles of benzoic acid kg of benzene Let we take 1 kg benzene as baru 300 mol = moler of lenzoic acid 1 kg moles of benzoic acid = 3.00 mol molar mass of benzoic acid = 122.12 g/mol mars of benzoic aad = moles X molar mas = 3.00 molx 122: 12 = 366.36 g g/mol = 366.36 X10-3 kq = 0.36636 kg - Total mass of solution : mass of benzene + mass of benzors acid lky + 0.36636 kg 1.36636 =

mars percent of benzoic auc= mass of benzolu alid Xoo Total mass of solution 0.36636 -X100 1.36636 = 26.81284581 % . = 26.81. percent by mass of benzoic and is | 26.81 y. 1