Question

Part A How many molecules of O2 are contained in a 10.0 L tank at 7.53 atm and 485 K? O1.14 x 1024 molecules 5.30 x 1024 molecules 5.69 x 1023 molecules 3.90 x 1024 molecules 2.28x 1024 molecules Request Answer Submit Provide Eeedhack

Answer 1

First determine the number of moles of O₂

This is easily done using the universal gas equation:
PV = nRT
n = PV/RT
n = 7.53 × 10.0 / 0.0821 × 485
n = 1.89 mol of O₂

1mol of O₂ contains 6.022 × 10²³ molecules
1.89 mol of O₂ contains 1.89 × 6.022 × 10²³

= 1.14 ×10²⁴ molecules of O₂