Question

Question 4 2 pts You will need to generate a set of graphs to answer this question. Concentration vs time data for the following decomposition reaction was collected at 300 K. The data is shown in the table below. What is the rate constant for the reaction at this temperature (in units of min ')? H202(aq)H20() + 1/2 O2(g) [H2O2] (mol/L) time (min) 0.09564 0 500 0.06968 0.05063 1000 1500 0.03685 2000 0.02680

Answer 1

Thi a ondenngaeim dbe Rote axprarsi fon tanden naaetln ar Init Cone g 239 kt at nuaetont at 2 Cone at ime t kz Rate const So a P 2.303 a) Ys gve trntne pasing thnagh ongi The slpe u give tne yatue nate Comstant

A В C Е 1 t(min) a(mol/lit) at(mol/lit (a/at) log(a/at) 2.303log(a/at) 0.09564 0 2 0 0.09564 1 1.37256 0.1375310.316735 500 0.09564 0.06968 0.05063 1.888999 0.276232 0.636161 1000 0.09564 0.03685 2.595387 0.414202 0.953907 5 1500 0.09564 0.0268 3.568657 0.552505 1.272418 2000 0.09564 st

1.4 В 1.2 Linear Fit of B 1.0 0.8 0.6 0.4 Equation y a b*x Adj. R-Square 1 Value Standard Error 0.2 В Intercept 0 В Slope 6.3603E-4 2.45185E-7 0.0 1500 0 500 1000 2000 time(min) 2.303log(a/ap)

From the plot, value of slop =6.36 x 10^-4

So rate constant = 6.36 x 10^-4 min^-1.