Question

Given:

1) NaOH$\rightarrow$ Na+(aq) + OH- (aq)

2) NaOH + H+ Cl-(aq)$\rightarrow$ H2O(l) + Na+(aq) + Cl-(aq)

3) Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq)$\rightarrow$ H2O(l) + Na+(aq) + Cl-(aq)

Show that equations 1 and 3 can be added algebraically to give equation 2.

Answer 1

Nach - Natcap.) + Oh case) can ③ Natcap.) + OH Cas.) + Ht cap.) + C1 Cap.) → Hores & Natcas.) + Ct cap.) Lean Adding en ② and ③ we have NaOH + Nat(as) + oH (as.) + Ht Cap.) + Cl case) Natcas.) tot cap. + Holl) + Natcap.) +ciras.) Now Cancel the species which are same on so Nate, and of case, are same on both side so it will be cancelled. And equation ① + becomes NaOH + H+ (as) + Cl cap.) → H20 (1) + Natcas.) t cicas.) s And this is same as Ean-② so Eqn ③ – Ean ① + Ean ②