The joint probability distribution for Xi and X2 is T1T2 f (1, 2)L22 for 1 1,2,3...

Question

Question

math Statistics-And-Probability

Answer 1

Answer #1

a) Y can take the values as 1, 2, 3, 4, 6, 9

So the PMF is

Y	1	2	3	4	6	9
P(y)	1/36	1/9	1/6	1/9	1/3	1/4

b) Z can take the values as 2,3 32 32

The values with the corresponding probabilities are

So the probability distribution is

Z				1		2	3
P(z)	1/12	1/18	1/6	7/18	1/6	1/18	1/12

Answer 2

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