Using Excel for economic service analysis
Economic service analysis of Challenger
| Year | Discount factor | O&M cost | PV (O&M) | Cumulative (O&M) | Cumulative (O&M) + Initial Cost | Salvage value | PV (Salvage value) | NPV | (A/P,12%,n) | EUAC |
| A | B | C | D=C*B | E | F=E+80000 | G | H=G*B | I=F-H | J | K = I*J |
| 1 | 0.89286 | 10000.00 | 8928.57 | 8928.57 | 88928.57 | 70500.00 | 62946.43 | 25982.14 | 1.12000 | 29100.00 |
| 2 | 0.79719 | 11200.00 | 8928.57 | 17857.14 | 97857.14 | 69090.00 | 55078.13 | 42779.02 | 0.59170 | 25312.26 |
| 3 | 0.71178 | 12544.00 | 8928.57 | 26785.71 | 106785.71 | 67708.20 | 48193.36 | 58592.35 | 0.41635 | 24394.87 |
| 4 | 0.63552 | 14049.28 | 8928.57 | 35714.29 | 115714.29 | 66354.04 | 42169.19 | 73545.10 | 0.32923 | 24213.58 |
| 5 | 0.56743 | 15735.19 | 8928.57 | 44642.86 | 124642.86 | 65026.96 | 36898.04 | 87744.82 | 0.27741 | 24341.27 |
| Discount factor | 1/(1+0.12)^n | |||||||||
| (A/P,i,n) | i((1 + i)^n)/((1 + i)^n-1) | |||||||||
Minimum EUAC is 24213.58 at 4 yrs, so the economic service life is 4 yrs of challenger
Economic service analysis of Defender
| Year | Discount factor | O&M cost | PV (O&M) | Cumulative (O&M) | Cumulative (O&M) + Initial Cost | Salvage value | PV (Salvage value) | NPV | (A/P,12%,n) | EUAC |
| A | B | C | D=C*B | E | F=E+55000 | G | H=G*B | I=F-H | J | K = I*J |
| 1 | 0.89286 | 9000.00 | 8035.71 | 8035.71 | 63035.71 | 45000.00 | 40178.57 | 22857.14 | 1.12000 | 25600.00 |
| 2 | 0.79719 | 10350.00 | 8250.96 | 16286.67 | 71286.67 | 42300.00 | 33721.30 | 37565.37 | 0.59170 | 22227.36 |
| 3 | 0.71178 | 11902.50 | 8471.96 | 24758.64 | 79758.64 | 39762.00 | 28301.81 | 51456.83 | 0.41635 | 21424.00 |
| 4 | 0.63552 | 13687.88 | 8698.89 | 33457.53 | 88457.53 | 37376.28 | 23753.30 | 64704.23 | 0.32923 | 21302.86 |
| 5 | 0.56743 | 15741.06 | 8931.90 | 42389.43 | 97389.43 | 35133.70 | 19935.81 | 77453.62 | 0.27741 | 21486.39 |
| Discount factor | 1/(1+0.12)^n | |||||||||
| (A/P,i,n) | i((1 + i)^n)/((1 + i)^n-1) | |||||||||
Minimum EUAC is 21302.86 at 4 yrs, so the economic service life is 4 yrs of defender
b.
As EUAC @ 5 yrs of Defender is 21486 which is less than minimum EUAC of challenger, the defender should be kept for 5 yrs before being replaced by challenger
Showing Formula in Excel for Challenger, defender can be calculated in similar way
| Year | Discount factor | O&M cost | PV (O&M) | Cumulative (O&M) | Cumulative (O&M) + Initial Cost | Salvage value | PV (Salvage value) | NPV | (A/P,12%,n) | EUAC |
| A | B | C | D=C*B | E | F=E+80000 | G | H=G*B | I=F-H | J | K = I*J |
| 1 | =1/(1.12)^A14 | 10000 | =C14*B14 | =D14 | =80000+E14 | 70500 | =G14*B14 | =F14-H14 | =0.12*((1 + 0.12)^A14)/((1 + 0.12)^A14-1) | =I14*J14 |
| 2 | =1/(1.12)^A15 | =C14*1.12 | =C15*B15 | =E14+D15 | =80000+E15 | =G14*0.98 | =G15*B15 | =F15-H15 | =0.12*((1 + 0.12)^A15)/((1 + 0.12)^A15-1) | =I15*J15 |
| 3 | =1/(1.12)^A16 | =C15*1.12 | =C16*B16 | =E15+D16 | =80000+E16 | =G15*0.98 | =G16*B16 | =F16-H16 | =0.12*((1 + 0.12)^A16)/((1 + 0.12)^A16-1) | =I16*J16 |
| 4 | =1/(1.12)^A17 | =C16*1.12 | =C17*B17 | =E16+D17 | =80000+E17 | =G16*0.98 | =G17*B17 | =F17-H17 | =0.12*((1 + 0.12)^A17)/((1 + 0.12)^A17-1) | =I17*J17 |
| 5 | =1/(1.12)^A18 | =C17*1.12 | =C18*B18 | =E17+D18 | =80000+E18 | =G17*0.98 | =G18*B18 | =F18-H18 | =0.12*((1 + 0.12)^A18)/((1 + 0.12)^A18-1) | =I18*J18 |
| Discount factor | 1/(1+0.12)^n | |||||||||
| (A/P,i,n) | i((1 + i)^n)/((1 + i)^n-1) | |||||||||
QUESTION 4: Exide Technologies think the operation system for their machine tools is too old...
Your client requests you to evaluate two different pump systems for a facility. Asuume an interest rate of 9% per year and each system has a life span of 15 years. System 1: Initial cost = $55,000 O&M cost = $2500 for the first year and increasing $100 per year for the remainder of the life span Salvage Value = $15,000 System 2: Initial cost = $50,000 O&M cost = $2000 for the first year and increasing $150 per year...
Your client requests you to evaluate two different pump systems for a facility. Asuume an interest rate of 9% per year and each system has a life span of 15 years. System 1: Initial cost = $55,000 O&M cost - $2500 for the first year and increasing $100 per year for the remainder of the life span Salvage Value = $15,000 System 2: Initial cost = $50,000 O&M cost = $2000 for the first year and increasing $150 per year...
Example 1 JJ company wants to replace the old machine. Machine is used in molding the components. The old machine was acquired three year ago. Its remaining useful life is 5 years and salvage value is $10,000. Book value of old machine is $70,000. Old machine cash operating cost is $20,000 per year. A new machine is the speed accelerating machine. Its initial cost is $ 150,000. New machine cash 's operating cost is $12,000 per year. Its useful life...
a. A new operating system for an existing machine is expected to cost $667,000 and have a useful life of six years. The system yields an incremental after-tax income of $195,000 each year after deducting its straight-line depreciation. The predicted salvage value of the system is $55,000. b. A machine costs $470,000, has a $38,000 salvage value, is expected to last eight years, and will generate an after-tax income of $105,000 per year after straight-line depreciation. Assume the company requires...
Dexcon Technologies, Inc., is evaluating two alternatives to produce its new plastic filament with tribological (.e., low friction) properties for creating custom bearings for 3-D printers. The estimates associated with each alternative are shown below. Using a MARR of 20% per year, which alternative has the lower present worth? Method First Cost M&O Cost, per Year Salvage Value Life DDM $-170,000 $-45,000 LS $-410,000 $-15,000 $35,000 4 years $0 2 years The present worth for the DDM method is $...
NPV: Taxes and Accelerated Depreciation Assume that United Technologies is evaluating a proposal to change the company's manual design system to a computer-aided design (CAD) system. The proposed system is expected to save 9,000 design hours per year; an operating cost savings of $45 per hour. The annual cash expenditures of operating the CAD system are estimated to be $200,000. The CAD system requires an initial investment of $550,000. The estimated life of this system is five years with no...
Bailey Corporation is considering modernizing its production by
purchasing a new machine and selling an old machine. The following
data have been collected on this investment:
Testbank Question 57 Bailey Corporation is considering modernizing its production by purchasing a new machine and selling an old machine. The following data have been collected on this investment: Old Machine Cost Accumulated amortization Remaining life Current salvage value Salvage value in 4 years Annual cash operating costs $40,000 $20,000 4 years $5,000 New...
can you solve it by using Excel
Alternative Comparison-Different Lives 5.17 Dexcon Technologies, Inc. is evaluating two alter- natives to produce its new plastic filament with tribological (i.e., low friction) properties for creat- ing custom bearings for 3-D printers. The esti- mates associated with each alternative are shown below. Using a MARR of 20 % per year, which al- ternative has the lower present worth? LS DDM Method -370,000 -164,000 First cost, $ -21,000 -55,000 M&O cost, $/year 30,000...
The Schroeder Corporation is considering the purchase of an system that costs $55,000, with a 5 year life and no salvage value. The system will generate cost savings over its life of $15,000 per year. The company has a required rate of return of 20% on all its inverstments. 1. Compute the Internal Rate of Return of this investment. 2. Should the company make the investment and why or why not?
Testbank Question 55 Bailey Corporation is considering modernizing its production by purchasing a new machine and selling an old machine. The following data have been collected on this investment: New Machine Old Machine Cost Accumulated amortization Remaining life Current salvage value Salvage value in 4 years Annual cash operating costs $40,000 $20,000 4 years $5,000 $0 $18,000 Cost Estimated useful life Salvage value in 4 years Annual cash operating costs $19,000 4 years $5,000 $14,000 The income tax rate is...