Question

ΔΗ - 2 9 σκη Imol NaOH 0.506 mol NaOH.

convert qrxn to deltaH

Answer 1

In a reaction, the heat released i.e. q_rxn can be different from change in Enthalpy, $\Delta H$.

In this case, it is given that

$\frac{\Delta H}{1\;mol\;NaOH}=\frac{q_{rxn}}{0.506\;mol\;NaOH}$

Thus, we will have,

$\frac{\Delta H\times (0.506\;mol\;NaOH)}{1\;mol\;NaOH}=q_{rxn}$

This will imply that,

$q_{rxn}=0.506\Delta H$

Thus, the heat released during reaction is 0.506 times change in enthalpy i.e. $q_{rxn}=0.506\Delta H$