Question

1. (20 points) The drawing of a part is given on the right. All dimensions are in cm A quality technician inspected the inside diameters of a sample group of finished products. She reported that the sample inside diameters' average is 9.011 cm, SD 0.010 cm (normal distribution). Calculate what percentage of the inside diameters meet the design specifications. 60.00。 45.00 の9+0.025 03+0.05u 810.05 1240.08 _14±0.1- 014+0.03

Please solve the question and show all the steps to get to the final solution(s).

Answer 1

P(9-0.025 < X< 9+0.025)

Z = (X - mean)/sd =(X - 9.011)/0.010

hence

P ( 8.975<X<9.025 )

=P ( −3.6<Z<1.4 )

= 0.919