
2. (30 points) If the dissolved oxygen (DO) concentration measured during a BOD test is 9...
Problem 4 (10 Points). You collect a sample of wastewater and run a BOD test. To run this test, you mix 25 mL of the wastewater sample with clean (unseeded) dilution water to bring the total volume in the bottle to 300 ml, After measuring the initial dissolved oxygen concentration, you cap the BOD bottle and monitor the dissolved oxygen concentration of the diluted sample in the BOD bottle as a function of time (see Figure below). Previous tests have...
QUESTION 3 a) After a point of wastewater discharge, the dissolved oxygen (DO) concentration is found as 83.33% of the saturation DO. The remaining BOD after 5 days at the point of discharge is 10.13 mg/L. The BOD rate constant determined in the laboratory under standard conditions is 0.115/day. The saturation DO concentration in the river water is 9 mg/L. The deoxygenation and the reaeration rate coefficients are 0.25/day and 0.45/day, respectively. The river travels at a velocity of 0.12...
7. A BOD test is run using 100 mL of treated wastewater effluent mixed with 200 mL of dilution water (containing no BOD). The initial DO of the mix is 9.0 mg/L After 5 days, the DO is 4.0 mg/L. After a long period of time, the DO is 2.0 mg/L, and it no longer seems to be dropping. Assume nitrification has been inhibited so that only carbonaceous BOD is measured (a) What is the 5-day BOD of the wastewater?...
7. You work for the Ministry of Environment to evaluate the maximum ultimate BOD concentration in the effluent of a new wastewater treatment plant such that the oxygen deficit never exceeds 1.5 mg/L in the receiving river. During dry weather (i.e., lowest river flow), the wastewater will be diluted 10 times in the river water and the river water contains 3.5 mg/L of ultimate BOD. Also during dry weather, you know that the river velocity after the wastewater discharge would...
6 MGD of wastewater with a dissolved oxygen concentration of 0.9 mg/L is discharged to a river flowing at 40 ft'/sec. The river initially is saturated with oxygen. The saturation DO is 11.30 mg/L. The oxygen content of the river (mg/L) immediately after mixing is most nearly: (conversion factor: 7.48 gal= 1 ft') 1.30 9. 34 9.00 8.85 7.24 other, write your answer
6 MGD of wastewater with a dissolved oxygen concentration of 0.9 mg/L is discharged to a river...
The following data were measured in a 40 liter bioreactor by a dissolved oxygen electrode during a cycle in which the air supplied was shut-off and then restarted. (The system automatically restarted the air supply when the DO reached a minimal acceptable value.) The cell concentration at the time the data were collected was 0.96 g/L Time (s Conc. O, (mg/L 6.33 6.33 6.33 5.78 5.22 4.66 4.10 3.55 2.99 2.43 2.54 3.12 3.59 3.95 4.24 4.45 4.59 4.74 4.87...
Example 7.15: According to the following information, determine whether a fish, which requires 6 \(\mathrm{mg} / \mathrm{L}\) dissolved oxygen, would survive in the river.Given:Waste water flow rate \(\left(\mathrm{Q}_{w}\right)=1.2 \mathrm{~m}^{3} / \mathrm{s}\)River flow rate \(\left(\mathrm{Q}_{r}\right)=10 \mathrm{~m}^{3} / \mathrm{s}\)River temperature \(\left(T_{r}\right)=15^{\circ} \mathrm{C}\)River ultimate \(\mathrm{BOD}\left(\mathrm{BOD}_{r}\right)=2.3 \mathrm{mg} / 1\)River reaeration rate \(=0.4\) per day for BOD testBOD concentration was initially \(9 \mathrm{mg} / \mathrm{l}\), after 5 days was \(6 \mathrm{mg} / 1\) and after an indefinitely long period of time was \(2.5 \mathrm{mg} /...
Two samples are brought to the laboratory for the BOD test. Please calculate BOD5 for both, using laboratory DO data. a. For sample A, seeded BOD test was performed. The initial DO concentration in the BOD bottle, which was filled with 2 mL of sample and 298 mL of seeded dilution water, was 8.9 mg/L just after preparation. After an incubation period of five days, the final DO concentration was reported as 1.8 mg/L. Meanwhile, DO concentration in the seed...
A BOD test is run with 150 mL of wastewater mixed with 150 mL of deionized water. The initial DO = 8.5 mg/L, the DO after 5 days = 4.2 mg/L, and the DO ultimately levels off at 1.7 mg/L. Assume all nitrification has been inhibited and the temperature remains constant. a) Calculate the CBOD5 (y5, mg/L) b) Calculate the ultimate CBOD (Lo, mg/L) c) Calculate the CBOD remaining after 5 days (L5, mg/L) d) Calculate the deoxygenation rate constant...
4- The biochemical oxygen demand (BOD) test is conducted over a period of time in days. The resulting data follow: Time (days):2 4 6 8 10 12 14 16 18 20 BOD (mg/liter): 0.6 0.7 15 1.9 2.1 2.6 2.9 3.7 3.5 3.7 3.8 (a) Test for significance of regression using o 0.01. Find the P-value for this test. What conclusions can you draw? (b) Estimate the standard errors of the slope and intercept (c) Test the hypothesis that Bo...