Question

At an outdoor market, a bunch of bananas attached to the bottom of a vertical spring of force constant 16.0 N/m is set into oscillatory motion with an amplitude of 20.0 cm. It is observed that the maximum speed of the bunch of bananas is 39.2 cm/s. What is the weight of the bananas in newtons?

Answer 1

Solution)

wA=39.2*10^-2

or w=0.392/0.2

=1.96 rad/s

Now, for a spring,

w=(k/m)^0.5

or 1.96=(16/m)^0.5

or m=4.16 kg

Now, we know weight=mg

=40.81 N (Ans)

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Good luck!:)