Question

Question 1 (6 points) Two college instructors are interested in whether or not there is any variation in the way they grade math exams. They each grade the same set of 10 exams. The first instructor's grades have a variance of 59.2. The second instructor's grades have a variance of 72.5. Test the claim that the first instructor's variance is smaller. (In most colleges, it is desirable for the variances of exam grades to be nearly the same among instructors.) The level of significance is 10%. (Recall: that the larger of the 2 variances needs to be in the numerator as the test is 1-tailed to the right) Calculate the test statistic of the F-test about two variances. (answer to 3 decimal places) Your Answer: Answer Video game ANOVA A Blizzard Entertainment is testing a new game on three different groups. Each group represents a different target market for the game. The developer collects scores from a random sample from each group. Raw data is shown first and then the Analysis of Variance has been run below it. Use to answer the following questions. Group Group Group C A В 101 101 151 108 149 109 98 160 198 107 112 186 126 160 111 Anova: Single Factor SUMMARY Group Average Variance Count Sum Group A 5 525 105 28.5 Group B 5 698 139.6 395.3 Group C 1944.7 5 754 150.8 ANOVA Ecrit Sourca of Variation SS df MS F P-value Between Groups Within Groups 5700.4 2850,2 3.610133 3.885294 0.059229 9474 12 789.5 Total 15174.4 14
Please answer all 9 questions

Answer 1

Page No. Date Sg.2 = 72.5. :. Ftest test shahrtic = NI = 12.5 59.2 - 1.225 [1.225 Here P value = o.osgaza o-059229 > 0.05. T: Decision rule Ano: that fail to reject the null hypothesis all means are equal.

Page No. Date 0.3 F critical = 3.885294 Ftest (calculated) = 3.610133 .. Here, Ecal feritical. - Decision Rule! Ang! fail to reject the null hypothesis that all means are equal 0.4] closest in meal Group A - Group B = 139.5-105= 34.5 I Group B - Groupe l = 150.8-139.5=11.3 I Group A - Groupel = 150.8-105] =45-8 ... Grouro and groupe me dorest Answer : Grove B Grovec

Date 1.51 least variation Group A. Which team hus least varighion Team 5 Team s - a.7 closest menn Team I-Team 4 = 43- 42.66667 = 0.33333 Closest mean Ans: 1 Team I Team 4 xvale . K13SZ 2 - : fail to reject the that all means are equal null hypothesis

Date Q. g) Ecritical value = 3.47805 F calculated value = 2.060393. . E calculated value < Fcritical value L. fail to reject the null hypothesis that all means are equal.