Question

A meterstick (L-1 m) has a mass of m-0.17 kg. Initially it hangs from two short strings: one at the 25 cm mark and one at the 75 cm mark. "What is the tension in the left string? Net You currently have submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. 2. Now the right string is cut! What is the initial angular acceleration of the meterstick about its pivot point? (You may assume the rod pivots about the left string, and the string remains vertical) rad/s? Suare You currently have submissions for this question. Only 10 submission are allowed, You can make 10 more submissions for this question. What is the tension in the left string right after the right string is cut? N You currently have submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. After the right string is cut, the meterstick swings down to where it is vertical for an instant before it swings back up in the other direction. What is the angular speed when the meterstick is vertical? rad/s Sant You currently have submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question What is the acceleration of the center of mass of the meterstick when it is vertical? m/ s amt You currently have submissions for this question. Only 10 submission are allowed. You can make 10 more submissions for this question. "What is the tension in the string when the meterstick is vertical? NG You currently have submissions for this question. Only 10 submission

Answer 1

1)

Tension, T = mg/2 = 0.17 x 9.8/2 = 0.833 N

2)

Net torque, T = 0.17 x 9.8 x 0.25 = 0.417 Nm

Moment of inertia, I = (0.17 x 1/12) + (0.17 x 0.25^2) = 0.025 kg m^2

Angular acceleration, a = 0.417/0.025 = 16.82 rad/sec^2

3)

Acceleration, a = 0.25 x 16.82 = 4.21 m/s^2

Tension, T = 0.17 (9.8 - 4.21) = 0.95 N

4)

mg x 0.25 = 0.5 I ω^2

(0.16 x 9.8 x 0.25) = 0.5 x 0.025 ω^2

ω = 5.6 rad/sec

5)

Acceleration, a = 5.6^2 x 0.25 = 7.84 m/s^2

6)

Tension, T = (0.17 x 7.84) + (0.17 x 9.8) = 3 N

7)

Option (a)

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