Capital recovery = -50000 * (A/P, 10%,12) + 10000 * (A/F, 10%,12)
= -50000 * 0.146763 + 10000 * 0.046763
= -6870.53
First option is correct answer
Given that i = 10% per year and the data below: Alternative Project A First Cost($)...
Question 6 (10 points) The machines shown below are under consideration for an improvement to an automated candy bar wrapping process. Machine C Machine D First cost, $ –50,000 –65,000 Annual cost, $/year –9,000 –10,000 Salvage value, $ 12,000 25,000 Life, years 3 6 (Source: Blank and Tarquin) Based on the data provided and using an interest rate of 8% per year, the Capital Recovery “CR”of Machine D is closest to: (All the alternatives presented below were calculated using compound...
The machines shown below are under consideration for an improvement to an automated candy bar wrapping! process. First cost, $ Annual cost, $/year Salvage value, $ Life, years (Source: Blank and Tarquin) Machine C 40,000 -15,000 12.000 Machine D -75,000 -10,000 25.000 Based on the data provided and using an interest rate of 5% per year, the Annual Worth “AW" of Machine C is closest to (All the alternatives presented below were calculated using compound interest factor tables including all...
Question 3 (10 points) The machines shown below are under consideration for an improvement to an automated candy bar wrapping process. Machine C Machine D First cost, $ -50.000 -65,000 Annual cost, S/year -9,000 -10,000 Salvage value, S 12.000 25,000 Life. years (Source: Blank and Tarquin) Based on the data provided and using an interest rate of 8% per year, the correct equation to calculate the Annual Worth "AW" of Machine C is: AWC-50,000(P/A, 8%, 3) + 12,000(F/A, 8%, 3)...
Date Table 2 (MARR-10%) First cost, S Annual cost, S per year Salvage value, S Life, years -40,000 -25,000 20,000 10 -75,000 15,000 7,000 a) Conduct PW analysis b) Conduct AW analysis c) Calculate capitalized cost for N d) Calculate capital recovery for MN
Date Table 2 (MARR-10%) First cost, S Annual cost, S per year Salvage value, S Life, years -40,000 -25,000 20,000 10 -75,000 15,000 7,000 a) Conduct PW analysis b) Conduct AW analysis c) Calculate capitalized cost...
AV UI d Perallell Project Select the "best answer to the following multiple choice question Question 16 (6.5 points) "The State of Georgia decided to fund a program for restoring and maintaining local museums. The first cost is $250,000 now, and an additional cost of $80,000 every 8 years forever. The perpetual equivalent annual worth (in years 1 through infinity of this program at an interest rate of 16% per year is equal to: **The answers presented below were calculated...
Question 7 (10 points) The machines shown below are under consideration for an improvement to an automated candy bar wrapping process. Machine C Machine D First cost, $ -50,000 -65,000 Annual cost, $/year 9,000 - 10,000 Salvage value, s 12,000 25,000 Life, years (Source: Blank and Tarquin) Based on the data provided and using an interest rate of 8% per year, the correct equation to calculate the Annual Worth of Machine D is: AWD--65,000(P/A, 8%, 6) +25,000(F/A, 8%, 6) -10,000...
The
cash flow diagram is the most important
Problem-6 The following cash aows hasu interest rale of 10% per year. сотр -800.000 -10,000 150.000 First cost. S Annual cost, S/ycar Salvage value, $ Life, vears -200,000 40.000 20,000 Use Annual worth analysis to choose the best alternative CFD CFD
Problem-6 The following cash aows hasu interest rale of 10% per year. сотр -800.000 -10,000 150.000 First cost. S Annual cost, S/ycar Salvage value, $ Life, vears -200,000 40.000 20,000 Use...
*The State of Georgia decided to fund a program for restoring and maintaining local museums. The first cost is $250,000 now, and an additional cost of $80,000 every 8 years forever. The perpetual equivalent annual worth (in years 1 through infinity) of this program at an interest rate of 12% per year is equal to: **The answers presented below were calculated using the appropriate factors from interest tables including all their decimal places** -$110,000 -$304,202 -$36,504 -$31,996
Question 12 For alternatives shown in the table below you are trying to decide which alternative you should choose based on their capitalized costs (CC). Use an interest rate of 10% per year. Machine A Machine B 240,000 First cost (AED) 20,000 Annual maintenance cost per year, AED 5,000 2.300 Periodic cost every 10 years, AED 10,000 Salvage cost 2000 Life. vears Match the closest correct answers for the below questions: Calculate the present value of the maintenance costs for...
Calculate the present worth of the Alternative "A". Assume the interest rate is 2% per year, compounded annually. Alternative A Initial cost $1,000,000 Annual maintenance cost $50,000 Overhaul cost every 4 years $200,000 Salvage value $400,000 Useful life 40 years