Question

The vapor pressure of ethanol is 54.68 mm Hg at 25°C.

How many grams of chlorophyll, C₅₅H₇₂MgN₄O₅, a nonvolatile, nonelectrolyte (MW = 893.5 g/mol), must be added to 206.4 grams of ethanol to reduce the vapor pressure to 53.60 mm Hg ?

ethanol = CH₃CH₂OH = 46.07 g/mol.

.............g chlorophyll

Answer 1

According to Raount's Law Lowering of vapour Pressure po_P = XB. po XB = soonte mole fraction X = solute more (n) solute mole (n) + solvent more (N) O no Weight (w) Moleintas Weight . x >>n so XB= solute mole (y) 1 . Solvent MORIN) - WA na WB MB Сім) Na ma. So, 89.4 - Ws y en la MBWA pis solvent Vapour Pressure = 54.68 mm ty P= solution " " = 53.60 mm Hg. (Chlorophy) AB= soonte Weight = 2. olure MRI solute Molecules & ga. Weight MOL

Solvent Was Ma= solvent Weight = 206ing sovent molecules = 46.079 พาช ๒) MB WA : MB.X WA WB 110i WB = (54.68-53.60 x 89315 7 x 206:48 ( 34.68 ) 46.07 / Mon WB = 11:08) x 184418.48 J4.68 46.07 WB = 4323.24g 1 suits WB=79008g. 79.06 g Chlorophyll | Angwes