Question

1. From the starting point (from rest) a car travels a distance Stotal in a straight line with a constant acceleration. At the distance Stotal the car has reached a speed of Vfinal. Determine how much time this took and the value of the constant acceleration. Take Stotal-200 m and Vfinal 15 m/s

From the starting point (from rest) a car travels a distance stotal in a straight line with a constant acceleration. At the distance stotal the car has reached a speed of vfinal. Determine how much time this took and the value of the constant acceleration. Take stotal = 200 m and vfinal = 15 m/s.

Answer 1

​​​​​if body is moving with uniform acceleration we use equations of motion in kinematics.
a = acceleration from equation of motion, total distance travelled in time t is s = ut + 1/2 at^2 s = (0) t + 1/2 at^2 s = 1/2 at^2 rightarrow 1 and S_total = Average velocity times time S-Total = (u + v_final/2) t 200 = (0 + 15/2) t Total time of journey from 1, t = 400/15 = 26.67 sec from 1, a = 2s/t^2 = 2 times 200/t^2 = 2 times 200/(400/15)^2 = 0.5625 m/s^2