Question

$: Alcohol Dehydration Product : Unknown Sample ID Sample Type Injection Volume ISTD Amount :C:\GCsolution Data dehydration re$Assign the peaks to the appropriate Alkene structure by comparing the retention time to those of the pure Alkene chromatogram (the one to compare to is the first one that has the structures drawn in pen) .. calculate Peak area for the second page do it for all the peaks except solvent peak which is pentane. Peak area= height*Width@1/2height

Also, Calculate the percent of each compound %X= AreaX/ AreaX+ AreaY+AreaZ*100

Answer 1

ANSWER:

1) Comparing retention time

• The solvent peak (pentane) is the peak at 0.500 min.
• The 3-methylcyclohexene appears at 1.322 min
• The peak at 2.261 min is the 2-methylcyclohexanol
• Only with the retention times it is difficult identify if 1-methylcyclohexene is the peak at 1.41.3 min or the peak at 1.528 min

2) Calculate peak Area and % of compound

Peak	Retention time	Height (intensity)	Width (min)	Area	% compound
1	0.344	685	0.151	685 x 0.151 = 103.435	103.435 x 100 / 2516.547 = 4.11 %
2	0.500 (solvent)	----	----	----	----
3	1.322	4398	0.176	4398 x 0.176 = 774.048	774.048 x 100 / 2516.547 = 30.76 %
4	1.413	3954	0.085	3954 x 0.085 = 336.09	336.09 x 100 / 2516.547 = 13.36 %
5	1.528	3533	0.273	3533 x 0.273 = 964.509	964.509 x 100 / 2516.547 = 38.33 %
6	2.261	2435	0.139	2435 x 0.139 = 338.465	338.465 x 100 / 2516.547 = 13.45 %
		Total area:		2516.547