Question

Tswer: D. 36) One mole of potassium sulfate contains:

Answer 1

Answer:-

(36) -

As we know that a mole is defined as the amount of substance containing chemical particles like atoms , molecules or ions equal to the Avogadro's number i.e 6.023 $\times$ 10²³ e.g.

1 mole Al = 27 g Al = 6.023 $\times$ 10²³ Al atoms

1 mole H₂O = 18 g H₂O = 6.023 $\times$ 10²³ H₂O molecules

1 mole NaCl  = 58.5 g H₂O = 6.023 $\times$ 10²³ NaCl molecules

therefore

1 mole potassium sulfate contains = 1 mole K₂SO₄  = 174.26 g K₂SO₄ = 6.023 $\times$ 10²³ K₂SO₄ molecules  (i.e the answer)

(60) -

Given:-

percentage of carbon (C) = 26.68 %

percentage of hydrogen (H) = 2.24 %

percentage of oxygen (O) = 71.08 %

As we know that empirical formula is the formula of compound which gives the simple whole number ratio of atoms of various elements present in one molecule of the compound.

therefore following table in which simple whole number ratio of carbon (C) , hydrogen (H) and oxygen (O) present in the compound can be calculated as follows:-

Element	Symbol	percent by mass (%)	Atomic mass	Moles of element (% / At. mass)	Simple molar ratio	Simplest whole no. molar ratio
Carbon	C	26.68	12	26.68 / 12 = 2.22	2.22 / 2.22 = 1	1
Hydrogen	H	2.24	1	2.24 / 1 = 2.24	2.24 /2.22 = 1	1
Oxygen	O	71.08	16	71.08 / 16 = 4.44	4.44 / 2.22 = 2	2

So

correct empirical formula of compound = C₁H₁O₂

or

correct empirical formula of compound = CHO₂ (i.e the answer)