Question

Given that

$\mu=120,\sigma=0.30$

The standard error of mean is

$se=\frac{\sigma}{\sqrt{n}}=\frac{0.30}{\sqrt{40}}=0.0474$

The usual range of values is within 2 standard deviations of mean. Here usual range of values will be

$\mu\pm 2se=120\pm 2\cdot 0.0474=(119.9052,120.0948)=(119.91,120.09)$

Yes.It is unusual that you would have randomly sampled 40 cans with a mean equal to 119.9 ounces because it is not within range of a usual event namely with 2 standard deviations of the mean of the sample means.

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