Question

The answers are in red. Please explain all the parts! Especially Part f!

continuous uniform distribution with a minimum time of 14 minutes and maximum time of 26 minutes. Complete parts a f The commute time to work for a particular employee follows a) Calculate the value of f(x). f(x) 0.083 (Type an integer or decimal rounded to three decimal places as needed.) b) What are the mean and standard deviation for this distribution? The mean of this distribution is 20 minutes (Type an integer or decimal rounded to two decimal places as needed.) The standard deviation of this distribution is 3.46 minutes. (Type an integer or decimal rounded to two decimal places as needed.) c)What is the probability that the employee's next commute to work will require less than 21.5 minutes? 0.625 (Type an integer or decimal rounded to three decimal places as needed.) d) What is the probability that the employee's next commute to work will require more than 16.5 minutes? 0.792 (Type an integer or decimal rounded to three decimal places as needed.) e) What is the probability that the employee's next commute to work will require between 18 and 23 minutes? 0.417 (Type an integer or decimal rounded to three decimal places as needed.) f) What commute time represents the 40th percentile of this distribution? 18.8 minutes (Type an integer or decimal rounded to one decimal place as needed.)

Answer 1

non :- xn uniform a = 14 [a, b] ; b = 26 a) f(x) = 0.083 26-14 9) 4 saat 10.089 b) Mean atb = 14 +26 = [20] Standard deviabion = biasanya dipe V12 = 13.46 121.5 6) plxces) Sander Jil a plc21.5) 21,5 dx 12 14 21.5-14 12 0.625 d) P(x3109) do 12 16.5 16.5 T2 24.1405 [0-432 c) P118 < X<2 2) = 10 de LX(23) 18 y goth peocortile be to mo percantile be xo Lada = 0.40 - I = 0.40 12 & Xo-14 = 0.40 2) Xo = [18. 87