Given : Mt = 36 g or 0.036 kg , Ct = 815 J/kg°c , Tt = 12°c , Mw= 119 g or 0.119 kg , Tf = 41.2°c
Goal : Initial temperature of water (Tw)= ?
Constant : heat capacity of water (Cw)= 4186 J/kg°c
Solution:
According to the conservation of energy,
Heat loss by water = Heat gain by thermometer
MwCw(Tw-Tf) = MtCt(Tf-Tt)
(0.119)(4186)(Tw-41.2) = (0.036)(815)(41.2 - 12)
498.134(Tw-41.2) = 856.728
Tw - 41.2 = 1.72
Tw = 42.92°c
Answer : Tw = 42.92°c
ure of the object itself should not change. However, if a significant amount of heat flows...
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