Question

5. Five tons of iron are cooled from 1500°C to 110°C, resulting in a change in enthalpy for the iron of- 21 kJ/mol. To do this, the iron is cooled by dumping it in 2 tons of cold water at 5'C. What fraction of the water is vaporized?

how do i approach this problem???

Answer 1

olven molar calculate ma enthalphy Change 2 21 KT mass of fer 55-845 g/mol heat released by five hors of yon, Quavon arvon = 5 tonsx 907184-749 x 2113 x 1 mol ton mor 55-8459 -95, 254, 397.7 KJ / 55.845. a pesx lot you 1705, 692.5 KJ = 1-7077 105 KJ. This heat released by raron is absorbed by water Heat absorbed by water a 9.5x107 lo7 This heat is used in converting water at sc to water at 100°c and then. some hould water converted to gaseous water. first of calculate heat used in coating remperature wabor a mucher x oxOT 2 2 tons & 907184 749 4:184 J x (1005). ton goc 721, 175.58 10 . 7. 2Rx 10 kg. so heat used in phase change of water e houd ro gas) & 4.7050 kg - 7.212 x 105 x 44,532, 800 R 984, 49 2.5 = 9.8450 x 10 kg. calcolate mass of water that converted to steam in tons Con nn molesy flust

Sthap 2 @40-67 kg mol used heat required a mo hox ou up 98458X LOG IT a n X 40-67 kJ mo) mass of h mo z 8. 2880x moter 24, 206-8 moles in sonst 24, 206.8 moies onstruxto motey x 18-015289&Iton mol 907184-749 mhor a 6.48 tons. So fraction of water a vaporized mwater (vapoved - Joral mass of wateu. 0.48 tons 2 tons 10-24