Question

A mixture of hydrocarbons contains 37.8%heptane,C7H16, 14.4%nonane, C9H20, and 47.8%octane, C8H18. The mixture is combusted in an excess of oxygen. What mass of CO2 is generated from the combustion of 13.8 kg13.8 kg of the mixture?

mass of CO2: _______kg

kg

Answer 1

a glum- In the mixture 37.86. heptene present 14.4.1. nonase 7.8 octone Total mace of mixture : 13.8 kg _Gamla_present = 37.8_* 13:8 3 5.2kg 100 CO 420 present = 14.4 100 X 13.8 32 kg- C&His present = 4208 x 13.8 606 kg: moles of Ca Hloe - 52107' 3 52ma loogimol Moles of Carzo 2000g 1289 Imol & 15.6 mol . Moles of co12 = 66 og = 57.9 mol 11491mol CzHiG + 1102 760 + 8H20 2 C8H18 + 2502 16CO2 + 18H20 _ Cq 420 +14002 -> loco2 + 9002

L1 mol of so, 52 mol CAHIG will produced produce 7 moles 364 moles of coa of coo i moler so, 15.6 of moles C₂ H18 will produce produce o nolee of cos 124.8 moles of co 1 mol of so, 57.9 Carro moles produce a molee of coo will produce 52101 moles of co, " Total molee of co2 produced - = 364 + 124.8+52101 = 1009.9. molese Molas. mase of cov: 449. Irud I mass of co2 produced = 1009.amolx y - a 44.4 kg
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